Assembly: Tambah Nombor Genap & Dapatkan purata

Kadang-kadang aku pun konpius tapi soalan mcm ni biasa keluar:
Write an assembly language program segment to add two even number N1 and N2. The average is computed and stored in a varible named AVG(Assume AVG has been declared as an 8 bit length)
jawapan(aku rasa x berapa bagus):
.MODEL SMALL
.STACK 64
.DATA
TWO db ?
i dw ?
count dw ?
Sum dw ?
AVG db ?
N1 dw ?
N2 dw ?
.CODE
main proc far
MOV Sum,0
MOV TWO,2
MOV count, 0
MOV i,0
start: INC i
Mov AX,i
Mov N2, AX ;AX to N2
DIV TWO
CMP AH, 1 ;Kalau nombor ganjil bahagi dua mesti dapat baki 1
JE start
ADD BX, i ;N1 + N2
Mov N1, BX
INC count ;Kira berapa kali nombor genap ditambah
CMP i, 10
JGE stop
JMP start
stop: MOV Sum, BX
Mov AX, Sum
DIV count ; Bahagi jumlah dengan bilangan tambah
MOV AVG, AL; Masuk nilai purata ke dalam AVG
INT 21h
main endp
end main

Mari kita fahamkan sesama:
Bila bahagi degan operasi DIV, AX akan ada dua nilai berbeza dekat AH & AL.
Dalam AL akan ada nilai bahagi, dalam AH akan ada baki.
Oleh itu, kita CMP(compare) AH dengan 1 sebab setiap nombor ganjil kalau dibahagi 2 akan ada baki 1.

P/S: Rasanya pos yang aku buat sebelum ni patut kena rombak.

Masih banyak lagi kena belajar. ......bersambung

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